Product Differentiation Knowledge Base
Oligopolistic Competition product differentiation? (product differentiation) Two firms produce differentiated products and compete in price. The market demand for rm 1's product is q1 (p1; p2) = 100-2p1+p2; and the market demand for firm 2's product is q2 (p1; p2) = 100 + p1 - 2p2: Both rms have identical marginal cost c = 10: What are the equilibrium prices, quantities and prots?
Cost Leadership and product differentiation? Can someone help? I need to find 3 industries that have volume-profit relationships. Which are implementing cost leadership strategies? Which are implementing differentiation strategies? or both? or none? Cost leadership: focuses on gaining advantages by reducing costs below their competitors Diff. Strategies: attributes, features, location, timing, relationships between itself and its customers, linkages within or between firms well, its asking 3 industries or markets... Can you explain why you put the answers you did? I am not sure of the question itself! =) Thanks! IF YOU ARE GOING TO SAY "DO YOUR HOMEWORK YOURSELF" PLEASE DO NOT RESPOND! OBVIOUSLY I DO NOT KNOW HOW TO ANSWER THIS QUESTION!!
Product Differentiation in Agriculture? Name other examples of agricultural products that have attempted to differentiate themselves. How have they differentiated their product? (Hint: Precut chicken is one example mentioned in the
Proof of cross product differentiation.? I am a 14 year old taking calculus and I have a stupid question. How do we prove that the use of the product rule is valid when differentiating a cross product function. Eg. P cross R = L I am not lying people! I am learning calculus on my own and I AM fournteen.
Marketing(Product differentiation)? Can you give an example about the followings: 1)physcial attribute differentiation>>>one example 2)service differentiation>>>one example 3)personel differentiation>>>one example 4)location differentiation >>>one example 5)image differentiation>>>one example personel=personnel sorry~
Product differentiation occurs when: ? A. Customers perceive there is a difference between products. B. There are physical differences between the products. C. Advertising proves that the products are different. D. Firms offer products that have different colors and sizes. Im thinking C. cause the rest are ridicoulous
differentiation, product rule problem....? 2(x+4)^2 im not sure if i use the product rule or not. is the answer just 4(x+4)? or does the two in front mean i need to use the product rule. none of my text books have an example like this....argghh, confused.
Differentiation (product rule)? y = ( x - 1 ) ( x^2 + 3 )^3/2 How do i apply product rule to this? please explain and show me the steps.. i'm stuck after i bring the 3/2 power down.. Thanks !
Differentiation (Product Rule)? Differentiate the following functions with respect to x (wrt x) by product rule. (a) y = (x + 7)^10 (x^2 + 2)^7 This is my workings: y = (x + 7)^10 (x^2 + 2)^7 dy/dx = (x + 7)^10 7(x^2 + 2)^6 (2x) + (x^2 + 2)^7 10(x + 7)^9 (1) dy/dx = 7(x^2 + 2)^6 (x + 7)^10 + 10(x + 7)^9 (x^2 + 2)^7 dy/dx = (x + 7)^9 (x^2 + 2)^6 (24x^2 + 98x + 20) The answer is of course (x + 7)^9 (x^2 + 2)^6 (24x^2 + 98x + 20). I how how they got (x + 7)^9 (x^2 + 2)^6, but I don't understand how they got (24x^2 + 98x + 20)...Please explain, thanks. ========== I posted wrongly...Should be product rule...not chain rule...=x
differentiation product rule? ln[ (2x^3)-(3x^2)+(7) ] would i just use the product rule for this? which in this case id put u as ln, and then du as 1/x and then v as 2x...etc and then dv as 6x....etc then id end up with ln(6x^2-6x) + (2x^2 - 3x + 7/x) which i then dunno what to do from there!?!? .....well now i have no idea what to do....
differentiation product and quotient rule.? y=(x+1)^2(2x-1) to find dy/dx, we use the product rule, Y^1=UV^1 + VU^1 then let U be (x+1)^2 let v be (2x-1) U^1=2(x+1) v^1=2 y^1=(x+1)^2(2) + (2x-1).2(x+1) then how do i continue? the answer key show that the next step is: y^1=2(x+1)[x+1+2x-1] =2(x+1)[3x] =6x(x+1) how do I get that?
Calculus I: Differentiation (Product Rule)? Can someone please validate my workings and answer for the following question? f(x) = (2x-1)(3x-2)(5x+1) d/dx = ? Using the product rule these are the workings I get: d/dx y = (2x-1)(3x-2)d/dx(5x+1)+(5x+1)d/dx((2x-1)(3x-2)) = (2x-1)(3x-2)(5)+ (5x+1)(2x-1)d/dx(3x-2)+(3x-2)d/dx(2x-1) = 5(2x-1)(3x-2) + 3(5x+1)(2x+1) + 2(3x-2) < Final answer Can I simplify further? Our given formulae is d/dx (f.g) = f d/dx g + g d/dx f It was applied twice and my answer was confirmed on PhysicsForums.com Wolfram Alpha is never consistent with my answers. Never mind, I added my bracket and it worked out fine. It is only for f/g problems that wolfram does me wrong. Thank you much
Differentiation - do i need to use the product rule here?? Given: f(x) = sin (2x) e^x Calculate f ' (x), f '' (x) and f ''' (x) to give the Taylor polynomial equation where n=2 and a=0. If you don't know how to do Taylor polynomials, still answer whether I should use the product rule here, please!! Thanks. :)
Can someone correct my homework ? It's about differentiation (product, quotient and chain ...)? Could you please tell me what's wrong and what i've done wrong (or even just the correct answer might be enough) 1. y=3(x+4)^4 My answer : f '(x)= 12(x+4)^3 2. y= (3x-4)/4-x My answer : f '(x)= 8/(4-x)^2 3.y= (x^2 +4)(2x+1) My answer : f '(x)=6x^2+2x+8 4 y=4(3x-1)^5 My answer : f '(x)=60(3x-1)^4 5 y=x^3(4-3x) My answer : f '(x)=3x^2(4-3x) 6. y=(x+2)^3(2x-1)^2 My answer : f '(x)= (x+2)^2(2x-1)(8x+1) 7 y=4x-3/3x+5 My answer : f '(x)=29/(3x+5)^2 8 y=3(x^2+3x+1)^4 No idea how to do that........ 9 y=x^2/2x-1 My answer : f '(x)=2x^2-2x/(2x-1)^2 10 y=(3x+1)^4(2-x)^3 My answer : f '(x)=3(3x+1)^3(2-x)^2(7-7x)
Differentiation using the product rule? Hi, I was wondering whether anyone would be able to give me a clear to read and detailed walk through of how to differentiate the following function. y = ((2x - 1)^3)((x + 1)^3) I already have the answer in my book, but I need to know how to work towards the answer. I can get as far as differentiating U and V but after that I'm not sure what to do. Thanks for any help.
Product rule differentiation. I can't along from here, need help with steps as possible? 1. (x+2)^2 (x-5)^2 Answer: [(x+2)^2 * 2(x-5) * 1] + [(x-5)^2 * 2(x+2) *1] = 2(x-5) (x+2)^2 + 2(x+2) (x-5)^2 I don’t know how to get to the final answer from here, which is supposed to be: (5x-4) (x+2) (x-5)^2 2. x^2(x^2+x-1)^3, the final answer is x(8x^2+5x-2) please show me the steps. Are there certain rules for differentiating these or what? I don’t get it, should we learn the steps?
Differentiation using Product Rule? I need help with this question, its been driving me insane, and the expansion alone took up nearly a whole page - can someone please tell me how I need to do this and what the actual answer is please? y = (3x + 1)^4 (2x - 3)^3 I got - dy/dx = 216x^5 - 288x^4 - 1350x^3 - 1566x^2 + 864x - 324 I doubt I got the correct answer.
using product rule in differentiation/derivatives? could someone please give me a step by step explanation of how to differentiate the following. there was only one example in the book and i couldnt seem to be able to apply it to the exercise.... x (1 + 3x) ^5 my main question is how do u add u.dv/dx and v.du/dx if there aren't any like terms? thanks, 10 pts to the first one from whom i understand it from
Differentiation using chain, product & Quotient Rules? Hi everyone, having trouble with these three, i've been asked to differentiate these using chain product and quotient rules, if anyone can help me with any of the three it would be much appreciated. a) y = sin3 (6 – 3x) (b) y = sqr(cosx) c) y = sin (4θ -7) + cos (7 - 4θ) Thankyou
Trouble with Calculus differentiation problem using product rule and chain rule? The problem is: Compute the Second Derivative of Sin (g(x)) at x=2, assuming that g(2) = π/4 , g`(2) = 5 , and g``(2) = 3. Remember, you are looking for the second derivative. Here is what I get: Y = Sin (g(x)) Y` = (Cos g(x)) (g`(x)) Y`` = (Cos g(x)) (g``(x)) + (- Sin g(x)) (g`(x)) Y`` = (Cos g(2)) (g``(2)) + (- Sin g(2)) (g`(2)) Y`` = (Cos π/4) (3) + (- Sin π/4) (5) Y`` = ((2)^(1/2)/2) (3) + (-(2)^(1/2)/2) (5) Y`` = -(2)^(1/2) Here is what the book says: Y`` = (Cos g(x)) (g``(x)) + (- Sin g(x)) (g`(x))2 Y`` = (-11) (2)^(1/2) What am I doing wrong? Whoops - the book says: Y`` = (Cos g(x)) (g``(x)) + (- Sin g(x)) (g`(x))^2
Product differenciation in a monopolistical market: If the toothpaste market is monopolistically competitive, product differentiation will take place in which of the following forms? a) different varieties of toothpaste -- including whitening agents b) differentiation in the locations that certain toothpastes are available c) quality differences among the various brands d) all of the above
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